Natural numbers from 1 to 100 is a set of the first 100 natural numbers, with 1 as the natural number and 100 as the largest one. Natural numbers being part of the number system includes all the positive integers from 1 to infinity. These are also called counting numbers as they do not include zero or negative numbers. The set of natural numbers is a classification under the bigger set of real numbers including only the positive integers, but not zero, fractions, decimals, and negative numbers.
In this article, let's learn natural numbers from 1 to 100 and find their sum with formula and solved examples.
| 1. | Natural Numbers 1 to 100 Chart |
| 2. | Sum of Natural Numbers 1 to 100 |
| 3. | Examples of Natural Numbers from 1 to 100 |
| 4. | Practice Questions on Natural Numbers from 1 to 100 |
| 5. | FAQs on Natural Numbers from 1 to 100 |
Natural Numbers 1 to 100 Chart
A chart of natural numbers 1 to 100 will help you to list down all the natural from 1 to 100. So, 100 is the last natural number in the list of natural numbers from 1 to 100. This is made with the help of a simple formula in which we add 1 to the previous number to obtain the next number. In other words, these are all consecutive numbers starting from 1 till 100. 1 is the smallest natural number in the list.
Sum of Natural Numbers 1 to 100
The natural numbers from 1 to 100 can be written as 1, 2, 3, 4,5…….100 is an arithmetic progression (A.P). The sum of all natural numbers 1 to 100 can be calculated using the formula, S= n/2[2a + (n − 1) × d], where n is the total number of natural numbers from 1 to 100, d is the difference between the two consecutive terms, and a is the first term. There are a total of 100 natural numbers, so n = 100.
Thus, a = 1, d = 1 and n = 100
Let's calculate the sum of the natural numbers 1 to 100
The sum of an A.P,
S = n/2[2a + (n − 1) × d]
S = 100/2[2 + (100 – 1) × 1]
S = 50 [2 + 99]
S = 5050
Therefore, the sum of natural numbers from 1 to 100 is 5050.
Important Notes:
- 1 is the smallest natural number.
- There are a total of 100 natural numbers from 1 to 100.
- Natural numbers are counting numbers only starting from 1.
- The sum of natural numbers 1 to 100 is 5050.
Topics Related to Natural Numbers 1 to 100
Check these articles related to the concept of natural numbers 1 to 100.
- Odd Numbers
- Even Numbers
- Even and Odd Numbers
- Whole Numbers
FAQs on Natural Numbers 1 to 100
What Are the Natural Numbers 1 to 100?
Natural numbers 1 to 100 are all those numbers, within this range, that are all consecutive numbers starting from 1 till 100. The natural numbers from 1 to 100 are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99 and 100.
How to Find the Sum of Natural Numbers 1 to 100?
The sum of all natural numbers from 1 to 100 is 5050. The total number of natural numbers in this range is 100. So, by applying this value in the formula: S = n/2[2a + (n − 1) × d], we get S=5050.
What is the Average of Natural Numbers from 1 to 100?
The average of natural numbers 1 to 100 is 100. This is calculated by using the formula of average, which states that Average = Sum of all values/Total number of values. Here, the sum of values is 5050 and the total number of natural numbers from 1 to 100 is 100. So, average = 5050/100 = 50.5. Therefore, 50.5 is the average of natural numbers 1 to 100.
Which is the Largest Natural Number in the List of Natural Numbers 1 to 100?
100 is the largest natural number in the list of natural numbers from 1 to 100. The next natural number will be 101 which is greater than 100. So, 100 is the greatest natural number in the list of even numbers 1 to 100.
What Is the Formula to Find the Sum of Natural Numbers 1 to 100?
The list of natural numbers 1 to 100 is well arranged in an arithmetic sequence. Thus, we can simply use the formula of the sum of n terms in the arithmetic progression, that is S = n/2[2a + (n − 1) × d], to calculate the formula for the sum of natural numbers.
